Retrieve the start times of members' bookings

For each member in the members table, the join has found all the matching member ids in the bookings table. For each match, it's then produced a row combining the row from the members table, and the row from the bookings table.

Obviously, this is too much information on its own, and any useful question will want to filter it down. In our query, we use the start of the SELECT clause to pick columns, and the WHERE clause to pick rows, as illustrated below:

That's all we need to find David's bookings! In general, I encourage you to remember that the output of the FROM clause is essentially one big table that you then filter information out of. This may sound inefficient - but don't worry, under the covers the DB will be behaving much more intelligently :-).

One final note: there's two different syntaxes for inner joins. I've shown you the one I prefer, that I find more consistent with other join types. You'll commonly see a different syntax, shown below:

select bks.starttime
        from
                cd.bookings bks,
                cd.members mems
        where
                mems.firstname='David'
                and mems.surname='Farrell'
                and mems.memid = bks.memid;

This is functionally exactly the same as the approved answer. If you feel more comfortable with this syntax, feel free to use it!